What is the midpoint (11.2,-2.2),(5.2,-10.2) ?

The midpoint (11.2,-2.2),(5.2,-10.2) is (8.2,-6.2)

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midpoint (11.2,-2.2),(5.2,-10.2)

midpoint

(11.2, - 2.2), (5.2, - 10.2)

(8.2, - 6.2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (11.2, - 2.2), (x_{2}, y_{2}) = (5.2, - 10.2)

= (\frac{5.2 + 11.2}{2}, \frac{- 10.2 - 2.2}{2})

Refine

= (8.2, - 6.2)

f (x) = (7 x^{3} + 2)^{\frac{1}{5}}

7 sin (4 (t + 7)) - 8

f (x) = (x + 2)^{\frac{1}{5}}

f (x) = 2 x - ln (2 x)

- 1 - x

What is the midpoint (11.2,-2.2),(5.2,-10.2) ?
The midpoint (11.2,-2.2),(5.2,-10.2) is (8.2,-6.2)