What is the extreme f(x)=x^4-6x^2 ?

The extreme f(x)=x^4-6x^2 is Minimum(-sqrt(3),-9),Maximum(0,0),Minimum(sqrt(3),-9)

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extreme f(x)=x^4-6x^2

extreme points

f (x) = x^{4} - 6 x^{2}

Minimum (- 3, - 9), Maximum (0, 0), Minimum (3, - 9)

Solution steps

f^{'} (x) = 4 x^{3} - 12 x

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{4} - 6 x^{2} : - 9

Minimum (- 3, - 9)

Plug

x = 0

into

x^{4} - 6 x^{2} : 0

Maximum (0, 0)

Plug

x = 3

into

x^{4} - 6 x^{2} : - 9

Minimum (3, - 9)

Minimum (- 3, - 9), Maximum (0, 0), Minimum (3, - 9)

y = - 2 x - 2

- \frac{1}{3} sin (\frac{x}{3})

f (x) = \frac{( 2 )}{( x + 2 ) ^{2}}

\frac{x - 1}{x ^{2} + 1}

f (x) = \frac{1 + x}{1 + x ^{2}}

What is the extreme f(x)=x^4-6x^2 ?
The extreme f(x)=x^4-6x^2 is Minimum(-sqrt(3),-9),Maximum(0,0),Minimum(sqrt(3),-9)