What is the domain of f(x)=(x/(x+3))/(x/(x+3)+3) ?

The domain of f(x)=(x/(x+3))/(x/(x+3)+3) is x -9/4

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domain of f(x)=(x/(x+3))/(x/(x+3)+3)

domain

f (x) = \frac{\frac{x}{x + 3}}{\frac{x}{x + 3} + 3}

x < - 3 or - 3 < x < - \frac{9}{4} or x > - \frac{9}{4}

Interval Notation

(- \infty, - 3) \cup (- 3, - \frac{9}{4}) \cup (- \frac{9}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{9}{4}, x = - 3

The function domain

x < - 3 or - 3 < x < - \frac{9}{4} or x > - \frac{9}{4}

\frac{6}{x} + 3

\frac{3 x + 3}{x + 2}

f (x) = - 2^{x}

(1, - 7), (- 4, 1)

f (x) = \frac{x - 5}{x - 11}

What is the domain of f(x)=(x/(x+3))/(x/(x+3)+3) ?
The domain of f(x)=(x/(x+3))/(x/(x+3)+3) is x<-3\lor-3<x<-9/4 \lor x>-9/4