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midpoint
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line (5,3),(3,4)line inverse of y=6x-x^2inverse critical ((y-3))/(y^2-3y+9)critical points extreme f(x,y)=9x^2-7extreme points intercepts of f(x)=x-3,-3<= x<0intercepts
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-8),(1,2) ?
The midpoint (-2,-8),(1,2) is (-1/2 ,-3)