What is the domain of f(x)=(sqrt(x))/(x^2+x-6) ?

The domain of f(x)=(sqrt(x))/(x^2+x-6) is 0 2

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domain of f(x)=(sqrt(x))/(x^2+x-6)

domain

f (x) = \frac{x}{x ^{2} + x - 6}

0 \leq x < 2 or x > 2

Interval Notation

[0, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 2, x = - 3

Combine real regions and undefined points for final function domain

0 \leq x < 2 or x > 2

f (x) = \frac{( e ^{x} )}{8 + e ^{x}}

f (x) = 3 x^{4} - 24 x^{2} + 18

y - 11 = 0 (x + 3)

f (x) = \frac{2 x - 3}{x ^{2} + 1}

f (x) = x^{2} + 9

What is the domain of f(x)=(sqrt(x))/(x^2+x-6) ?
The domain of f(x)=(sqrt(x))/(x^2+x-6) is 0<= x<2\lor x>2