What is the inverse of f(x)=(-2-\sqrt[3]{4x})/2 ?

The inverse of f(x)=(-2-\sqrt[3]{4x})/2 is -2(x^3+3x^2+3x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(-2-\sqrt[3]{4x})/2

inverse

- 2 (x^{3} + 3 x^{2} + 3 x + 1)

Solution steps

Replace

x

with

y

Solve for

- 2 (x^{3} + 3 x^{2} + 3 x + 1)

1 - e^{1 - x^{2}}

f (x) = cos (x - \frac{π}{2})

f (x) = 0.9

(a, b), (- a, 3 b)

\frac{2 x - 3}{x ^{2} + 4}

What is the inverse of f(x)=(-2-\sqrt[3]{4x})/2 ?
The inverse of f(x)=(-2-\sqrt[3]{4x})/2 is -2(x^3+3x^2+3x+1)