What is the intercepts of y=x^2+4x ?

The intercepts of y=x^2+4x is X Intercepts: (0,0),(-4,0),Y Intercepts: (0,0)

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intercepts of y=x^2+4x

intercepts

y = x^{2} + 4 x

X Intercepts : (0, 0), (- 4, 0), Y Intercepts : (0, 0)

Solution steps

x -

axis interception points of

x^{2} + 4 x : (0, 0), (- 4, 0)

y -

axis interception point of

x^{2} + 4 x : (0, 0)

X Intercepts : (0, 0), (- 4, 0), Y Intercepts : (0, 0)

f (x) = 2 x + 2 y - 8 = 0

f (x) = ln (x - 8)

18 x^{2} + 14 x

f (x) = \frac{1}{2 x - 6}

y = 9 x

What is the intercepts of y=x^2+4x ?
The intercepts of y=x^2+4x is X Intercepts: (0,0),(-4,0),Y Intercepts: (0,0)