What is the domain of f(x)=sqrt(36-t^2) ?

The domain of f(x)=sqrt(36-t^2) is -6<= t<= 6

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domain of f(x)=sqrt(36-t^2)

domain

f (x) = 36 - t^{2}

- 6 \leq t \leq 6

Interval Notation

[- 6, 6]

Solution steps

Find non-negative values for radicals:

- 6 \leq t \leq 6

The function domain

- 6 \leq t \leq 6

y = x, (- 1, 3)

f (x) = - \frac{2}{3} x - \frac{10}{3}

f (x) = 100000 - 2500 x

f (x) = \frac{1}{2} (x - 3)^{2} + 4

f (x) = - 2 x - 1

What is the domain of f(x)=sqrt(36-t^2) ?
The domain of f(x)=sqrt(36-t^2) is -6<= t<= 6