What is the monotone f(x)=-2^{x+1} ?

The monotone f(x)=-2^{x+1} is Decreasing:-infinity <x<infinity

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monotone f(x)=-2^{x+1}

monotone intervals

f (x) = - 2^{x + 1}

Decreasing : - \infty < x < \infty

Solution steps

f^{'} (x) = - ln (2) \cdot 2^{x + 1}

Find intervals:

Decreasing

: - \infty < x < \infty

Decreasing : - \infty < x < \infty

\frac{cos ( 8 θ ) - cos ( 4 θ )}{2}

2 - 3 cos (2 x)

lo g_{5} (x)

f (x) = - 2 x + 7

f (x) = 2 e^{- 0.7 t}

What is the monotone f(x)=-2^{x+1} ?
The monotone f(x)=-2^{x+1} is Decreasing:-infinity <x<infinity