What is the domain of f(x)=(x^2+4x-3)/(x^4-5x^2+4) ?

The domain of f(x)=(x^2+4x-3)/(x^4-5x^2+4) is x 2

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domain of f(x)=(x^2+4x-3)/(x^4-5x^2+4)

domain

f (x) = \frac{x ^{2} + 4 x - 3}{x ^{4} - 5 x ^{2} + 4}

x < - 2 or - 2 < x < - 1 or - 1 < x < 1 or 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, 1) \cup (1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2, x = 1, x = - 1

The function domain

x < - 2 or - 2 < x < - 1 or - 1 < x < 1 or 1 < x < 2 or x > 2

f (x) = \frac{9 x}{x ^{2} - 1}

(13 - x)^{\frac{1}{6}}

(1, 4), (3, 6)

f (x) = x - 4

\frac{2 x + 3}{x - 1}

What is the domain of f(x)=(x^2+4x-3)/(x^4-5x^2+4) ?
The domain of f(x)=(x^2+4x-3)/(x^4-5x^2+4) is x<-2\lor-2<x<-1\lor-1<x<1\lor 1<x<2\lor x>2