What is the domain of h(x)=sqrt(x-9) ?

The domain of h(x)=sqrt(x-9) is x>= 9

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domain of h(x)=sqrt(x-9)

domain

h (x) = x - 9

x \geq 9

Interval Notation

[9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

The function domain

x \geq 9

f (x) = 5 x^{4} - 10 x^{2} + 8

f (x) = x^{2} - 7 x - 30

f (x) = tan (e^{t}) + e^{t a n (t)}

7 x - 12 y = - 32

\frac{2}{x + 1} \cdot \frac{x}{x + 1}