What is the domain of f(x)= 4/(\sqrt[3]{1+x)} ?

The domain of f(x)= 4/(\sqrt[3]{1+x)} is x -1

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domain of f(x)= 4/(\sqrt[3]{1+x)}

domain

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = cos (2 x)

ln (\frac{x + 1}{2})

\frac{x ^{3}}{3} - x^{2} - 15 x

25 - x^{2} - x + 3

What is the domain of f(x)= 4/(\sqrt[3]{1+x)} ?
The domain of f(x)= 4/(\sqrt[3]{1+x)} is x<-1\lor x>-1