What is the extreme f(x)=-x^3+27x-52 ?

The extreme f(x)=-x^3+27x-52 is Minimum(-3,-106),Maximum(3,2)

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extreme f(x)=-x^3+27x-52

extreme points

f (x) = - x^{3} + 27 x - 52

Minimum (- 3, - 106), Maximum (3, 2)

Solution steps

f^{'} (x) = - 3 x^{2} + 27

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = - 3

into

- x^{3} + 27 x - 52 : - 106

Minimum (- 3, - 106)

Plug

x = 3

into

- x^{3} + 27 x - 52 : 2

Maximum (3, 2)

Minimum (- 3, - 106), Maximum (3, 2)

f (x) = \frac{4 x + 10}{2 x - 14}

f (t) = (\frac{1}{t - 2})

\frac{5}{1 - x}

y = - \frac{5}{2} x - 8

f (x) = - 3 x^{2}

What is the extreme f(x)=-x^3+27x-52 ?
The extreme f(x)=-x^3+27x-52 is Minimum(-3,-106),Maximum(3,2)