What is the asymptotes of f(x)=(2x)/(x^2-16) ?

The asymptotes of f(x)=(2x)/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(2x)/(x^2-16)

asymptotes

f (x) = \frac{2 x}{x ^{2} - 16}

Vertical : x = - 4, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2 x}{x ^{2} - 16} : x = - 4, x = 4

Horizontal Asymptotes of

\frac{2 x}{x ^{2} - 16} : y = 0

Slant Asymptotes of

\frac{2 x}{x ^{2} - 16} :

None

Vertical : x = - 4, x = 4, Horizontal : y = 0

x \cdot 7 - x

36 x^{2} + y^{2} = 36

f (x) = 7

(5, 6), (- 5, - 2)

f (x) = \frac{( 5 x + 4 )}{8 x - 7}

What is the asymptotes of f(x)=(2x)/(x^2-16) ?
The asymptotes of f(x)=(2x)/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=0