What is the domain of f(x)=(sqrt(2x-8))/(x^2-9) ?

The domain of f(x)=(sqrt(2x-8))/(x^2-9) is x>= 4

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domain of f(x)=(sqrt(2x-8))/(x^2-9)

domain

f (x) = \frac{2 x - 8}{x ^{2} - 9}

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x \geq 4

(- 5, 5), (2, - 3)

f (x) = x^{3} - 10

f (x) = \frac{x ^{3}}{3} - 2 x^{2} - 5 x

6 x^{2}

(0, 4), (1, 1)

What is the domain of f(x)=(sqrt(2x-8))/(x^2-9) ?
The domain of f(x)=(sqrt(2x-8))/(x^2-9) is x>= 4