What is the domain of f(x)=sqrt(6+x-x^2) ?

The domain of f(x)=sqrt(6+x-x^2) is -2<= x<= 3

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domain of f(x)=sqrt(6+x-x^2)

domain

f (x) = 6 + x - x^{2}

- 2 \leq x \leq 3

Interval Notation

[- 2, 3]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 3

The function domain

- 2 \leq x \leq 3

\frac{x ^{2}}{6 x ^{2} + 4}

f (x) = \frac{5 - x}{x ( x - 4 )}

g (x) = x^{2} - 3

\frac{x ^{2} - 2 x - 1}{x + 1}

(1, 0), (0, - 1)

What is the domain of f(x)=sqrt(6+x-x^2) ?
The domain of f(x)=sqrt(6+x-x^2) is -2<= x<= 3