What is the domain of f(x)=(sqrt(x+4))/(x-3) ?

The domain of f(x)=(sqrt(x+4))/(x-3) is -4 3

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domain of f(x)=(sqrt(x+4))/(x-3)

domain

f (x) = \frac{x + 4}{x - 3}

- 4 \leq x < 3 or x > 3

Interval Notation

[- 4, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 4 \leq x < 3 or x > 3

1 x + 1 y = 2

f (x) = x^{2} - 3 x - 2

f (x) = \frac{5}{x - 8}

f (x) = \frac{2 x + 3}{x + 4}

8 x^{\frac{1}{3}} + x^{\frac{4}{3}}

What is the domain of f(x)=(sqrt(x+4))/(x-3) ?
The domain of f(x)=(sqrt(x+4))/(x-3) is -4<= x<3\lor x>3