What is the domain of f(x)=sqrt(x-1)+sqrt(x-2) ?

The domain of f(x)=sqrt(x-1)+sqrt(x-2) is x>= 2

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domain of f(x)=sqrt(x-1)+sqrt(x-2)

domain

f (x) = x - 1 + x - 2

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

\frac{6}{x + 1}

f (x) = \frac{1}{∣ 4 - 8 x ∣ + 12}

(1, 6), (5, - 2)

f (x) = \frac{1}{x - 2}

f (x) = 36 - x^{2} - x + 1

What is the domain of f(x)=sqrt(x-1)+sqrt(x-2) ?
The domain of f(x)=sqrt(x-1)+sqrt(x-2) is x>= 2