What is the inverse of f(x)=x^2-18x ?

The inverse of f(x)=x^2-18x is 9+sqrt(x+81),9-sqrt(x+81)

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inverse of f(x)=x^2-18x

inverse

f (x) = x^{2} - 18 x

9 + x + 81, 9 - x + 81

Solution steps

y = x^{2} - 18 x

Replace

x

with

y

x = y^{2} - 18 y

Solve for

y, x = y^{2} - 18 y

9 + x + 81, 9 - x + 81

f (x) = 600 + 70 x

- x + 4 y = 20

f (x) = t - 36

f (x) = \frac{x + 6}{x + 2}

f (x) = 4^{x - 5}

What is the inverse of f(x)=x^2-18x ?
The inverse of f(x)=x^2-18x is 9+sqrt(x+81),9-sqrt(x+81)