What is the inverse of 2+\sqrt[3]{2-3x} ?

The inverse of 2+\sqrt[3]{2-3x} is -(x^3-6x^2+12x-10)/3

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inverse of 2+\sqrt[3]{2-3x}

inverse

- \frac{x ^{3} - 6 x ^{2} + 12 x - 10}{3}

Solution steps

Replace

x

with

y

Solve for

- \frac{x ^{3} - 6 x ^{2} + 12 x - 10}{3}

y = - (x - 5)^{2} - 3

x (sec^{2} (2 x) \cdot 2)

f (x) = \frac{5}{2 x}

(- 1.5) (7.9)

m = \frac{2}{9}, (9, 0)

What is the inverse of 2+\sqrt[3]{2-3x} ?
The inverse of 2+\sqrt[3]{2-3x} is -(x^3-6x^2+12x-10)/3