What is the critical x^4-5x^3+x^2+21x-18 ?

The critical x^4-5x^3+x^2+21x-18 is x=-1,x= 7/4 ,x=3

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critical x^4-5x^3+x^2+21x-18

critical points

x^{4} - 5 x^{3} + x^{2} + 21 x - 18

x = - 1, x = \frac{7}{4}, x = 3

Solution steps

x^{4} - 5 x^{3} + x^{2} + 21 x - 18

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = \frac{7}{4}, x = 3

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 5 x^{3} + x^{2} + 21 x - 18 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = \frac{7}{4}, x = 3

f (x) = \frac{1}{x - 3}

f (x) = 3 x^{2} - 6 x - 1

m = 0, (- 4, 2)

f (x) = x^{4} - 4 x^{2}

f (x) = - e^{x}

What is the critical x^4-5x^3+x^2+21x-18 ?
The critical x^4-5x^3+x^2+21x-18 is x=-1,x= 7/4 ,x=3