What is the domain of f(x)=(2x^2+10x+12)/(x^2+3x+2) ?

The domain of f(x)=(2x^2+10x+12)/(x^2+3x+2) is x -1

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domain of f(x)=(2x^2+10x+12)/(x^2+3x+2)

domain

f (x) = \frac{2 x ^{2} + 10 x + 12}{x ^{2} + 3 x + 2}

x < - 2 or - 2 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 2

The function domain

x < - 2 or - 2 < x < - 1 or x > - 1

f (x) = \frac{e ^{x}}{3 + e ^{x}}

f (x) = \frac{x - 2}{x ^{2} - 2 x - 3}

ln ∣ x ∣

4 x + 2 y = - 12

f (x) = \frac{1}{5} x^{3} - 2

What is the domain of f(x)=(2x^2+10x+12)/(x^2+3x+2) ?
The domain of f(x)=(2x^2+10x+12)/(x^2+3x+2) is x<-2\lor-2<x<-1\lor x>-1