What is the domain of f(x)=-sqrt(x+1) ?

The domain of f(x)=-sqrt(x+1) is x>=-1

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domain of f(x)=-sqrt(x+1)

domain

f (x) = - x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = e^{4 x - 5}

Y (x) = 3 x + 9, (- 2, 3)

f (x) = 8 x - 2

f (x) = 9 x - 7

f (x) = \frac{x ^{2} - 25}{x - 5}