What is the inverse of f(x)=(2x+9)/(2x-7) ?

The inverse of f(x)=(2x+9)/(2x-7) is (9+7x)/(2(-1+x))

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inverse of f(x)=(2x+9)/(2x-7)

inverse

f (x) = \frac{2 x + 9}{2 x - 7}

\frac{9 + 7 x}{2 ( - 1 + x )}

Solution steps

y = \frac{2 x + 9}{2 x - 7}

Replace

x

with

y

x = \frac{2 y + 9}{2 y - 7}

Solve for

y, x = \frac{2 y + 9}{2 y - 7}

\frac{9 + 7 x}{2 ( - 1 + x )}

f (x) = \frac{( x + 5 )}{x - 6}

y = e^{x}

- \frac{2 x}{( x + 1 ) ^{2} ( x - 1 ) ^{2}}

18 x^{4} - 108 x^{2}

- 6 x - 2 y = 7

What is the inverse of f(x)=(2x+9)/(2x-7) ?
The inverse of f(x)=(2x+9)/(2x-7) is (9+7x)/(2(-1+x))