What is the domain of f(x)=sqrt(x^2-5x+4) ?

The domain of f(x)=sqrt(x^2-5x+4) is x = 4

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domain of f(x)=sqrt(x^2-5x+4)

domain

f (x) = x^{2} - 5 x + 4

x \leq 1 or x \geq 4

Interval Notation

(- \infty, 1] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 4

The function domain

x \leq 1 or x \geq 4

f (x) = \frac{3 x - 8}{2 x + 1}

f (x) = 4 x^{2} + 12 x + 3

f (x) = 2 x^{2} - 4

2 x + y = 4, (1, 2)

\frac{2}{x - 2}

What is the domain of f(x)=sqrt(x^2-5x+4) ?
The domain of f(x)=sqrt(x^2-5x+4) is x<= 1\lor x>= 4