What is the domain of f(x)=((2x^3-5))/(x^2+x-6) ?

The domain of f(x)=((2x^3-5))/(x^2+x-6) is x 2

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domain of f(x)=((2x^3-5))/(x^2+x-6)

domain

f (x) = \frac{( 2 x ^{3} - 5 )}{x ^{2} + x - 6}

x < - 3 or - 3 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3

The function domain

x < - 3 or - 3 < x < 2 or x > 2

f (x) = \frac{x}{x ^{2} + 1}

y = f (x) = \frac{2 - 5 x}{6 - 6 x}

f (x) = 6 x

\frac{2 x}{x ^{2} + 2 x}

\frac{6}{\frac{x}{x + 6}}

What is the domain of f(x)=((2x^3-5))/(x^2+x-6) ?
The domain of f(x)=((2x^3-5))/(x^2+x-6) is x<-3\lor-3<x<2\lor x>2