What is the domain of f(x)=sqrt(2x-16) ?

The domain of f(x)=sqrt(2x-16) is x>= 8

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domain of f(x)=sqrt(2x-16)

domain

f (x) = 2 x - 16

x \geq 8

Interval Notation

[8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 8

The function domain

x \geq 8

f (x) = x^{2} (x - 3) (x - 6)

x + 3 - 2

3 x + 3 y = - 18

y = - \frac{1}{4} x + 5

g (x) = x - 6

What is the domain of f(x)=sqrt(2x-16) ?
The domain of f(x)=sqrt(2x-16) is x>= 8