What is the domain of f(x)=2sqrt(4-x^2) ?

The domain of f(x)=2sqrt(4-x^2) is -2<= x<= 2

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domain of f(x)=2sqrt(4-x^2)

domain

f (x) = 2 4 - x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

x^{5} - 5 x

f (x) = \frac{x ^{2} - x}{x ^{2} - 1}

x^{2} + 3 x + 6

x^{2} - 10 x + 20

\frac{2 x + 1}{x - 3}

What is the domain of f(x)=2sqrt(4-x^2) ?
The domain of f(x)=2sqrt(4-x^2) is -2<= x<= 2