What is the inverse of f(x)=((x+2))/((2x+1)) ?

The inverse of f(x)=((x+2))/((2x+1)) is (2-x)/(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=((x+2))/((2x+1))

inverse

f (x) = \frac{( x + 2 )}{( 2 x + 1 )}

\frac{2 - x}{2 x - 1}

Solution steps

y = \frac{x + 2}{2 x + 1}

Replace

x

with

y

x = \frac{y + 2}{2 y + 1}

Solve for

y, x = \frac{y + 2}{2 y + 1}

\frac{2 - x}{2 x - 1}

y = x^{2} - 5 x + 6

x - 12

f (x) = \frac{7 z + 6}{z - 7} + \frac{7 z + 3}{z - 7}

f (x) = (x - 2)^{2} + 3

f (x) = \frac{- 5 x}{- 2 x - 3}

What is the inverse of f(x)=((x+2))/((2x+1)) ?
The inverse of f(x)=((x+2))/((2x+1)) is (2-x)/(2x-1)