What is the range of 4sqrt(x-2)-8 ?

The range of 4sqrt(x-2)-8 is f(x)>=-8

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range of 4sqrt(x-2)-8

range

4 x - 2 - 8

f (x) \geq - 8

Interval Notation

[- 8, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = - 8

f (x) \geq - 8

2 e^{x} + 1

f (x) = x^{3} + 2 x^{2} + 1

3 x^{2} - 5 x + 7

tan^{2} (x)

(2 x^{2} + 2)^{3} (x^{2} - 1)^{2}