What is the domain of f(x)=(\sqrt[3]{x^5+3x-3})/(3x-2) ?

The domain of f(x)=(\sqrt[3]{x^5+3x-3})/(3x-2) is x 2/3

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domain of f(x)=(\sqrt[3]{x^5+3x-3})/(3x-2)

domain

x < \frac{2}{3} or x > \frac{2}{3}

Interval Notation

(- \infty, \frac{2}{3}) \cup (\frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{3}

The function domain

x < \frac{2}{3} or x > \frac{2}{3}

lo g_{10} (2 - x)

(- 1, 2), (- 1, - 4)

2 x^{2} - 5 x - 3

- (x - 1)^{3} + 2

- x^{3} + 12 x - 15

What is the domain of f(x)=(\sqrt[3]{x^5+3x-3})/(3x-2) ?
The domain of f(x)=(\sqrt[3]{x^5+3x-3})/(3x-2) is x< 2/3 \lor x> 2/3