What is the range of \sqrt[3]{x-1}-1 ?

The range of \sqrt[3]{x-1}-1 is -infinity <f(x)<infinity

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range of \sqrt[3]{x-1}-1

range

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

Inverse of

x^{3} + 3 x^{2} + 3 x + 2

Find the domain of each inverse function

Domain of

x^{3} + 3 x^{2} + 3 x + 2 : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

8 sin (7 x - 21) + 6

f (x) = 4 x - 28

y = 4 x + 1

f (x) = 3 x^{3} + 16

\frac{1}{x + 9}

What is the range of \sqrt[3]{x-1}-1 ?
The range of \sqrt[3]{x-1}-1 is -infinity <f(x)<infinity