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Popular >

range of f(x)=[x^2-4]

Solution

range

f (x) = [x^{2} - 4]

Solution

f (x) \geq - 4

+1

Interval Notation

[- 4, \infty)

Solution steps

Vertex of

x^{2} - 4 :

Minimum

(0, - 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (0, - 4)

f (x) \geq - 4

Popular Examples

domain of f(x)=x+1 domain

f (x) = x + 1

critical f(x)=(x-2)ex critical points

f (x) = (x - 2) e x

inverse of f(x)=(x-1)^2-3 inverse

f (x) = (x - 1)^{2} - 3

slope ofintercept (y+2)= 1/3 (x+9)slope intercept

(y + 2) = \frac{1}{3} (x + 9)

inverse of f(x)=(5x)/4 inverse

f (x) = \frac{5 x}{4}

Frequently Asked Questions (FAQ)

What is the range of f(x)=[x^2-4] ?
The range of f(x)=[x^2-4] is f(x)>=-4