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Popular >

midpoint (13,10),(3,-2)

Solution

midpoint

(13, 10), (3, - 2)

Solution

(8, 4)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (13, 10), (x_{2}, y_{2}) = (3, - 2)

= (\frac{3 + 13}{2}, \frac{- 2 + 10}{2})

Refine

= (8, 4)

Popular Examples

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f (x) = \frac{x - 2}{( x - 2 ) ^{2}}

extreme f(x)=x^4-8x^2+16 extreme points

f (x) = x^{4} - 8 x^{2} + 16

inverse of f(x)=\sqrt[3]{x+2}-1 inverse

domain of f(x)= 1/x-3 domain

f (x) = \frac{1}{x} - 3

critical (x-1)/(x^2+3)critical points

\frac{x - 1}{x ^{2} + 3}

Frequently Asked Questions (FAQ)

What is the midpoint (13,10),(3,-2) ?
The midpoint (13,10),(3,-2) is (8,4)