What is the intercepts of f(x)=(x+1)/(x^2-3x-4) ?

The intercepts of f(x)=(x+1)/(x^2-3x-4) is Y Intercepts: (0,-1/4)

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intercepts of f(x)=(x+1)/(x^2-3x-4)

intercepts

f (x) = \frac{x + 1}{x ^{2} - 3 x - 4}

Y Intercepts : (0, - \frac{1}{4})

Solution steps

x -

axis interception points of

\frac{x + 1}{x ^{2} - 3 x - 4} :

None

y -

axis interception point of

\frac{x + 1}{x ^{2} - 3 x - 4} : (0, - \frac{1}{4})

Y Intercepts : (0, - \frac{1}{4})

y = 6 x - 3

f (x) = 6 x^{2} + 1 - x

f (x) = ln (x + 2) + ln (x - 2)

x^{3} + 16

3 x + 20 = - 4 y

What is the intercepts of f(x)=(x+1)/(x^2-3x-4) ?
The intercepts of f(x)=(x+1)/(x^2-3x-4) is Y Intercepts: (0,-1/4)