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Popular >

distance (3,4),(-2,-1)

Solution

distance

(3, 4), (- 2, - 1)

Solution

52

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(3, 4)

and

(- 2, - 1)

is

= (- 2 - 3)^{2} + (- 1 - 4)^{2}

Simplify

= 52

Popular Examples

inverse of 3x^2+3 inverse

3 x^{2} + 3

inverse of f(x)=(7x)/(3x-8)inverse

f (x) = \frac{7 x}{3 x - 8}

critical f(x)=4x^3 critical points

f (x) = 4 x^{3}

symmetry 5x^2-20x+2=0 symmetry

5 x^{2} - 20 x + 2 = 0

domain of f(x)=(-4x-3)/(x-2)domain

f (x) = \frac{- 4 x - 3}{x - 2}

Frequently Asked Questions (FAQ)

What is the distance (3,4),(-2,-1) ?
The distance (3,4),(-2,-1) is 5sqrt(2)