What is the domain of f(x)=sqrt(((x+1))/(x-2)) ?

The domain of f(x)=sqrt(((x+1))/(x-2)) is x 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(((x+1))/(x-2))

domain

f (x) = \frac{( x + 1 )}{x - 2}

x \leq - 1 or x > 2

Interval Notation

(- \infty, - 1] \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x > 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x \leq - 1 or x > 2

f (x) = \frac{- 6 x + 2}{sin ( x )}

x^{2} + 6 x + 5

f (x) = 2 x + \frac{4}{x}

f (x) = \frac{4}{x + 1}

y = 3 cos (2 x)

What is the domain of f(x)=sqrt(((x+1))/(x-2)) ?
The domain of f(x)=sqrt(((x+1))/(x-2)) is x<=-1\lor x>2