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Popular >

range of f(x)=-5(x+1)^2-5

Solution

range

f (x) = - 5 (x + 1)^{2} - 5

Solution

f (x) \leq - 5

+1

Interval Notation

(- \infty, - 5]

Solution steps

Vertex of

- 5 (x + 1)^{2} - 5 :

Maximum

(- 1, - 5)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 5,

Vertex

(x_{v}, y_{v}) = (- 1, - 5)

f (x) \leq - 5

Popular Examples

range of x^4+8x^3 range

x^{4} + 8 x^{3}

parallel y= 1/2 x-3/2 parallel

y = \frac{1}{2} x - \frac{3}{2}

domain of f(x)=sqrt(2-x)+sqrt(x)domain

f (x) = 2 - x + x

slope of x-y=3 slope

x - y = 3

slope ofintercept y-(-8)=-2(x-0)slope intercept

y - (- 8) = - 2 (x - 0)

Frequently Asked Questions (FAQ)

What is the range of f(x)=-5(x+1)^2-5 ?
The range of f(x)=-5(x+1)^2-5 is f(x)<=-5