What is the inverse of f(x)= 1/2 x^3-6 ?

The inverse of f(x)= 1/2 x^3-6 is cube root of 2x+12

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inverse of f(x)= 1/2 x^3-6

inverse

f (x) = \frac{1}{2} x^{3} - 6

Solution steps

y = \frac{1}{2} x^{3} - 6

Replace

x

with

y

x = \frac{1}{2} y^{3} - 6

Solve for

y, x = \frac{1}{2} y^{3} - 6

\frac{7 + \frac{1}{x}}{\frac{1}{x}}

f (x) = 4 x + 5

2 lo g_{0.5} (- 5 x) + 4

1.25 t + 82

f (x) = 3 x^{3} + 6 x^{2}

What is the inverse of f(x)= 1/2 x^3-6 ?
The inverse of f(x)= 1/2 x^3-6 is cube root of 2x+12