What is the inverse of f(x)=9x^2+8x+6 ?

The inverse of f(x)=9x^2+8x+6 is (-4+sqrt(9x-38))/9 ,-(sqrt(9x-38)+4)/9

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inverse of f(x)=9x^2+8x+6

inverse

f (x) = 9 x^{2} + 8 x + 6

\frac{- 4 + 9 x - 38}{9}, - \frac{9 x - 38 + 4}{9}

Solution steps

y = 9 x^{2} + 8 x + 6

Replace

x

with

y

x = 9 y^{2} + 8 y + 6

Solve for

y, x = 9 y^{2} + 8 y + 6

\frac{- 4 + 9 x - 38}{9}, - \frac{9 x - 38 + 4}{9}

(4 - 9) - 5

f (x) = 1 + 4 + 5 x

f (x) = \frac{x ^{3}}{x ^{2} - 1}

y + 4 = 1 (x + 3)

f (x) = x - 5

What is the inverse of f(x)=9x^2+8x+6 ?
The inverse of f(x)=9x^2+8x+6 is (-4+sqrt(9x-38))/9 ,-(sqrt(9x-38)+4)/9