What is the asymptotes of r(x)=(6x^2+1)/(2x^2+x-1) ?

The asymptotes of r(x)=(6x^2+1)/(2x^2+x-1) is Vertical: x=-1,x= 1/2 ,Horizontal: y=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of r(x)=(6x^2+1)/(2x^2+x-1)

asymptotes

r (x) = \frac{6 x ^{2} + 1}{2 x ^{2} + x - 1}

Vertical : x = - 1, x = \frac{1}{2}, Horizontal : y = 3

Solution steps

Vertical asymptotes of

\frac{6 x ^{2} + 1}{2 x ^{2} + x - 1} : x = - 1, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{6 x ^{2} + 1}{2 x ^{2} + x - 1} : y = 3

Slant Asymptotes of

\frac{6 x ^{2} + 1}{2 x ^{2} + x - 1} :

None

Vertical : x = - 1, x = \frac{1}{2}, Horizontal : y = 3

f (x) = 5 sin (4 x + 2 π)

f (x) = x^{4} - 8 x^{2}

6 x + 2 y = 10

f (x) = \frac{( x - 2 )}{( x + 5 )}

x (x - 2)

What is the asymptotes of r(x)=(6x^2+1)/(2x^2+x-1) ?
The asymptotes of r(x)=(6x^2+1)/(2x^2+x-1) is Vertical: x=-1,x= 1/2 ,Horizontal: y=3