What is the domain of f(x)=(sqrt(2x+7))/(x-1) ?

The domain of f(x)=(sqrt(2x+7))/(x-1) is -7/2 1

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domain of f(x)=(sqrt(2x+7))/(x-1)

domain

f (x) = \frac{2 x + 7}{x - 1}

- \frac{7}{2} \leq x < 1 or x > 1

Interval Notation

[- \frac{7}{2}, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{7}{2}

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- \frac{7}{2} \leq x < 1 or x > 1

y = x^{2} + 1

\frac{2 x ^{2} - 3}{5}

\frac{x}{4 x + 9}

f (x) = \frac{2}{t ^{2} - 9}

f (x) = 2^{x^{5} - 1}

What is the domain of f(x)=(sqrt(2x+7))/(x-1) ?
The domain of f(x)=(sqrt(2x+7))/(x-1) is -7/2 <= x<1\lor x>1