What is the domain of (2x)/(x^2-1) ?

The domain of (2x)/(x^2-1) is x 1

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domain of (2x)/(x^2-1)

domain

\frac{2 x}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

3 x + 1

y = 2 x - 1, (1, 3)

f (x) = \frac{1 + x}{( 4 + x ) ^{2}}

\frac{x ^{2} - 3 x}{( x - 2 ) ^{2}}

2 x^{3} - 3 x^{2}

What is the domain of (2x)/(x^2-1) ?
The domain of (2x)/(x^2-1) is x<-1\lor-1<x<1\lor x>1