What is the domain of f(x)= 2/(sqrt(3-2x)) ?

The domain of f(x)= 2/(sqrt(3-2x)) is x< 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 2/(sqrt(3-2x))

domain

f (x) = \frac{2}{3 - 2 x}

x < \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2})

Solution steps

Find non-negative values for radicals:

x \leq \frac{3}{2}

Find undefined (singularity) points:

x = \frac{3}{2}

Combine real regions and undefined points for final function domain

x < \frac{3}{2}

f (x) = x + 13

f (x) = \frac{1}{2} x - \frac{7}{2}

\frac{2}{x + 4}

2 x + 3 y = 3

f (x) = x - 13

What is the domain of f(x)= 2/(sqrt(3-2x)) ?
The domain of f(x)= 2/(sqrt(3-2x)) is x< 3/2