What is the critical f(x)=(sqrt(1-x^2))/x ?

The critical f(x)=(sqrt(1-x^2))/x is x=-1,x=1

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critical f(x)=(sqrt(1-x^2))/x

critical points

f (x) = \frac{1 - x ^{2}}{x}

x = - 1, x = 1

Solution steps

\frac{1 - x ^{2}}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{1 - x ^{2}}{x} : - 1 \leq x < 0 or 0 < x \leq 1

\frac{1 - x ^{2}}{x}

is not defined at

x = 0

, therefore:

x = - 1, x = 1

(x - 1)^{3} + 2

\frac{x ^{3} + x ^{2} - 6 x}{4 x ^{2} + 4 x - 8}

f (x) = x - 4

x^{3} - x

(- 8, 0), (5, - 7)

What is the critical f(x)=(sqrt(1-x^2))/x ?
The critical f(x)=(sqrt(1-x^2))/x is x=-1,x=1