What is the domain of f(x)=(2x^2)/(1-x^2) ?

The domain of f(x)=(2x^2)/(1-x^2) is x 1

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domain of f(x)=(2x^2)/(1-x^2)

domain

f (x) = \frac{2 x ^{2}}{1 - x ^{2}}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

x^{2} - 10 x + 23

(4, - 1), (- 1, - 4)

ln (1 - x)

2 + 5 x

f (x) = \frac{( x + 9 ) ( x - 9 )}{x ^{2} + 81}

What is the domain of f(x)=(2x^2)/(1-x^2) ?
The domain of f(x)=(2x^2)/(1-x^2) is x<-1\lor-1<x<1\lor x>1