What is the asymptotes of f(x)= 1/((x+1)(x+2)) ?

The asymptotes of f(x)= 1/((x+1)(x+2)) is Vertical: x=-2,x=-1,Horizontal: y=0

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asymptotes of f(x)= 1/((x+1)(x+2))

asymptotes

f (x) = \frac{1}{( x + 1 ) ( x + 2 )}

Vertical : x = - 2, x = - 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{( x + 1 ) ( x + 2 )} : x = - 2, x = - 1

Horizontal Asymptotes of

\frac{1}{( x + 1 ) ( x + 2 )} : y = 0

Slant Asymptotes of

\frac{1}{( x + 1 ) ( x + 2 )} :

None

Vertical : x = - 2, x = - 1, Horizontal : y = 0

f (x) = 4 x - 2

y = - \frac{2}{3} + 5

f (x) = 27 x^{3} - 9 x + 1

f (x) = \frac{3 x + 12}{- 12 x + 4}

f (x) = \frac{7 x + 2}{x ^{2} - 5 x + 6}

What is the asymptotes of f(x)= 1/((x+1)(x+2)) ?
The asymptotes of f(x)= 1/((x+1)(x+2)) is Vertical: x=-2,x=-1,Horizontal: y=0