en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3+3x^2

Solution

extreme points

f (x) = x^{3} + 3 x^{2}

Solution

Maximum (- 2, 4), Minimum (0, 0)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

x^{3} + 3 x^{2} : 4

Maximum (- 2, 4)

Plug

x = 0

into

x^{3} + 3 x^{2} : 0

Minimum (0, 0)

Maximum (- 2, 4), Minimum (0, 0)

Popular Examples

critical 3x^2+6x+1 critical points

3 x^{2} + 6 x + 1

critical x^3+3x^2+3x+2 critical points

x^{3} + 3 x^{2} + 3 x + 2

inverse of y=3x+5 inverse

y = 3 x + 5

parity y=sqrt(((e^c))/(10x^{2/9))-x^2}parity

y = \frac{( e ^{c} )}{10 x ^{\frac{2}{9}}} - x^{2}

domain of f(x)=(2x)/(sqrt(x-8))domain

f (x) = \frac{2 x}{x - 8}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3+3x^2 ?
The extreme f(x)=x^3+3x^2 is Maximum(-2,4),Minimum(0,0)