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Popular >

range of-4.9t^2+9.8t

Solution

range

- 4.9 t^{2} + 9.8 t

Solution

f (t) \leq 4.9

+1

Interval Notation

(- \infty, 4.9]

Solution steps

Vertex of

- 4.9 t^{2} + 9.8 t :

Maximum

(1, 4.9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 4.9,

Vertex

(x_{v}, y_{v}) = (1, 4.9)

f (t) \leq 4.9

Popular Examples

slope ofintercept 5x+7y=4y-2 slope intercept

5 x + 7 y = 4 y - 2

inverse of 3x^3 inverse

3 x^{3}

domain of f(x)=((x/(x+5)))/((x/(x+5))+5)domain

f (x) = \frac{( \frac{x}{x + 5} )}{( \frac{x}{x + 5} ) + 5}

extreme f(x)=-(x+1)^2 extreme points

f (x) = - (x + 1)^{2}

extreme f(x)=x^6 extreme points

f (x) = x^{6}

Frequently Asked Questions (FAQ)

What is the range of-4.9t^2+9.8t ?
The range of-4.9t^2+9.8t is f(t)<= 4.9