What is the domain of \sqrt[4]{x^2-6x} ?

The domain of \sqrt[4]{x^2-6x} is x = 6

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domain of \sqrt[4]{x^2-6x}

domain

x \leq 0 or x \geq 6

Interval Notation

(- \infty, 0] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 6

The function domain

x \leq 0 or x \geq 6

8 x + 11 y = - 11

lo g_{\frac{1}{2}} (x)

cos (t)

(4, - 8), (- 6, - 2)

f (x) = x^{2} + 2 x - 2

What is the domain of \sqrt[4]{x^2-6x} ?
The domain of \sqrt[4]{x^2-6x} is x<= 0\lor x>= 6